Q2: Classic FizzBuzz Implementation
Output numbers from 1 to N, replacing multiples of 3 with 'Fizz', 5 with 'Buzz', and multiples of both with 'FizzBuzz'. Check compound conditions (multiples of 15) before individual factors.
FizzBuzz Loop
function fizzBuzz(n) {
const result = [];
for (let i = 1; i <= n; i++) {
if (i % 15 === 0) result.push('FizzBuzz');
else if (i % 3 === 0) result.push('Fizz');
else if (i % 5 === 0) result.push('Buzz');
else result.push(i.toString());
}
return result;
}
console.log(fizzBuzz(15));💡 Evaluating i % 15 first prevents multiples of both 3 and 5 from matching the earlier single-factor branches.
Key Takeaways
- Check for combined conditions (i % 15 === 0) before individual conditions.
- Demonstrates basic modulo arithmetic and control flow branching.
Knowledge Check
Why must the condition for 15 (or both 3 and 5) be checked first in FizzBuzz?